Wow ! Now this has me wishing I'd gone further than 5th grade ! I'll be up half the night with slide rules...calculator and ballistic charts...nervously pacing my reloading room ! Darn you Tiny Tim !! Ha ! Great question...I think..............
Exactly!!
One exception is the your example of the buzzsaw affect of the old black talon.
No doubt its design does affect terminal performance but you also have to consider that its the hydrostatic shock (energy) that has a greater effect on tissue damage.
These factors of terminal performance are designed into the bullet by the manufacturer. The manufacturers are usually very specific on twist rate and minimal/maximum speed that the bullet is designed for.
So say you pick a twist rate that like a 1:7.5 for a 6.5 Creedmore shooting 143-156 gr bullets @ 2700-2800fps. Would you pick the same 1:7.5 twist for a 6.5-300 Wby solely based on the idea that it will be more terminal affect? I wouldn't... because that 143 will probably self destruct as soon a it leaves the barrel.
I have seen the same thing with my Swifts on prairie dogs. 1-8 performance is much more dramatic than the 1-14 with the same bullet....I can tell you with 100% certainty that a 53 grain Vmax from a 1:8 twist AR15 has a much different terminal effect and result than the same bullet fired from my 1:14 .223.
A very noticeable difference on both reactions of the coyote and autopsies done. I can't see why the same result wouldn't hold true in larger calibers.
This calculation is assuming a 1:12" twist...
For quite a while I could not figure out where "720" came from. Turns out it's simply 12*60, or 12 bullet rotations per 60 seconds for a twist velocity in rpm.
Yes, you're right. Looks like I let my typing get ahead of my brain. Thank you for correcting that.MW, I believe the 720 in the formula is derived from 60 sec/minute x 12"/foot. The result is them divided by barrel twist rate. It simply gives a number that is a constant rather than constantly plugging in repetitive numbers. Thanks for the link. Good information there.
This is all stuff that's been tested on there Aberdeen Testing grounds. It's not theory. There's a strong science behind it. The army using non spinning flachettes in it's smoothbore tank guns isn't done on accident. Less rotations = less expansion = more armor penetration. Their 6 inch bolts aren't capable of penetrating 6 meters (yes, 6 meters) of hardened steel because someone happen chanced it. It was carefully planned and designed.
That said, the science isn't understood by most of us. Most of us aren't dynamic engineers and therefore aren't going to know the math. And nor is it needed to be known. All you need to know is that the faster the rotations the faster the expansion. There's a reason why they tell you not to use 22 hornet bullets in 22-250s with a fast twist. They come apart in flight before going very far. So obviously that will have an effect on a woodchuck versus one spinning quite slowly.
The easiest way to understand it is with a kid's ride. The faster you spin the harder it is to hang on.
Yes - the presumption, of course, is that the "black talon" holds together. Surprisingly, bullets hold together quite well. I have a load that uses 50 grain SBTHP bullets out of a .220 Swift, with a muzzle velocity of 4,400 f/s - got it out of an issue of Handloader back ages ago. In my 1:14 twist Ruger 77, that bullet is spinning 4,400*12/14 rps =226,286 rpm. Yet it holds together just fine to the target. At the target, however, it explodes violently from both impact speed and rotational force. In the old days, with less well-designed and manufactured bullets, .220 Swifts had a reputation for bullets blowing up midway to the target at only 4,000 f/s muzzle velocity.
So the presumption in my post was that a well-designed modern bullet would hold together - particularly a skived monolithic - and wreak havoc throughout the wound channel. Your example of a 6.5 at 2,600 f/s out of a 1:7.5 would not only be spinning faster (268,000 rpm), but the larger diameter of the bullet would result in tremendous internal forces on the bullet trying to tear it apart - yet they hold together well. Modern bullets are very well built.
It should also be noted that as a bullet expands, the expansion itself - owing to conservation of momentum - slows the bullet's rotation, not just the drag from the now-larger diameter. It's the opposite phenomenon we see when a spinning skater pulls in his or her arms, increasing the rotational rate of the spin, then extending arms to slow again.
But there is no question that the energy imparted longitudinally by the bullet transit along its path within the target far exceeds the energy imparted by rotational effects. At in-target velocities above about 2,200 f/s, the hydrostatic effects are very significant.
All that said, I suspect that rotational velocity is more critical to bullet stabilization than it is to wounding a critter. Even if the bullet were not spinning it would still expand and cause nearly the same damage and if the velocity is high enough, cause hydrostatic shock along the wound track.
crkckr
.......I have to shoot lead free in CA which requires a faster twist for like weight projectiles and have been addressing this issue for a while. Hopefully Steve from Hammer will chime in as he has some very interesting observations on this subject........
I know this isn't on topic with this thread, but wanted to know how successful you are at such ranges (especially first round hits). Theoretically, as you put it, we are talking several feet of drift or the equivalent to a couple mile per hour wind. Why not compensate for such a predictable displacement of the bullet? That's what a ballistic app can/will do for you, every modern one I've seen has such a feature. Couldn't you as the shooter be inducing error into the equation by simple neglect?I know there are people out there that calculate spin drift. I'm just not one of them. I do know as your Velocity changes so will the rate of the spin drift . It's really hard to calculate spin drift when you are messing with wind. So unless there is a way out there to eliminate ALL wind while taking that 2000 yards shot, how can you tell what the twist rate of the barrel dos to the bullet? You can't. It's just all Theory.
I believe I've read him post about faster twist equals potentially better terminal performance. Hopefully he will chime in.He's done a lot more penetration testing than most.