feelinducky
Well-Known Member
- Joined
- Oct 6, 2010
- Messages
- 419
During my latest bout of insomnia I came of with a question. Probably of no significance but sometimes I geek out. I have a 270wsm I'm loading for. I want to switch bullets but the new bullet is shorter from the ogive to tip and longer from the base to the ogive. The new bullet will have more shank in the case. How much potential powder weight do I sacrifice from changing bullets? I would like to use RL 26. I need to figure out how much more base is in the case then figure out how much displacement that would be then figure out how much RL26 fits into that displacement. So far I have:
Bullet #1
OAL 1.3240
Base to Ogive .7650
bullet diameter .277
Bullet #2
OAL 1.3170
Base to Ogive .9210
bullet diameter .277
.9210-.7650=.1385
I now figure there is an additional +.156" of base into the case.
Volume of a cylinder: V=3.14(r2)(H)
3.14(.0192)2(.156)=.009405
What I don't know is the weight per volume of the powder??? Where can I find this?
I may be doing this wrong but I'm sure there are a few math geeks out there that can figure this out.
Thanks
Bullet #1
OAL 1.3240
Base to Ogive .7650
bullet diameter .277
Bullet #2
OAL 1.3170
Base to Ogive .9210
bullet diameter .277
.9210-.7650=.1385
I now figure there is an additional +.156" of base into the case.
Volume of a cylinder: V=3.14(r2)(H)
3.14(.0192)2(.156)=.009405
What I don't know is the weight per volume of the powder??? Where can I find this?
I may be doing this wrong but I'm sure there are a few math geeks out there that can figure this out.
Thanks