Hi. This is my first post here. Like to shoot lr and starting on elr.
how to calculate how High a bullet fly on its Way to the Target. We fight and measure Wind at the Ground or near. But perhaps the Wind is stronger on lets sat 100 feet when we shoot atthe mile or longer distance. So is the a Way to calculate how High a bullet go on its path to the Target
To answer your question directly; the way the military used to teach this solution to their artillery crews was to use a simple formula:
4(t squared) sorry, I can't do exponents so I had to write t squared the way I did
t= the time of flight for total range
...the highest point of the bullet's flight in going a given range is equal to four times the square of the time of flight for the
total range.
So all you need to do is square the time of flight (to the range you are interested in) and multiply by 4 and you will get the height in yards. Multiply the answer by 3 and you will get the height in feet.
So lets say you shoot a .308 caliber, 168gr bullet at 1000 yards.
The time of flight for 1000 yards (from my ballistic software's trajectory chart) is approx. 1.6452 seconds
(1.6452 x 1.6452 ) x 12 = 32.5 feet
So the highest that the bullet will be, relative to the muzzle is, approximately 32.5 feet higher. If you are standing then you add the distance between the muzzle and the ground.
There is an error in this estimate due to rounding and precision but it's close enough to estimate wind conditions.
(Sorry, I had to correct my math but these are the correct formula and solutions)