...If your barrel is 3ft above the ground and you can manage to drop a bullet at the exact same time your bullet leaves the barrel when the bullet you dropped his the ground so will the bullet leaving your barrel
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They hit the ground at the same time, no matter how much that bullet is propelled thru air molecules? Not to mention aimed upward. Physics is taught in a vacuum for ease in understanding but none of the principles matter on an earth with fluidity of air, etc.
How many air molecules is the bullet hitting when dropped v the bullet flying 1000yds?
Both are right and both are wrong...
As mentioned, both scenarios have the same acceleration from gravity. But unless you have your barrel horizontal, you are indeed effectively "throwing" the rifle bullet into the air vs dropping the hand held bullet straight down, and thus not dropping it from 3 feet, but some larger amount.
Regarding the air resistance, the rate at which the bullet falls is only dependent on the molecules in the vertical direction. Acceleration is a vector, and has a specific direction as well as magnitude. For the two bullets, the falling acceleration is the same (air resistance upward component, and gravity downward component).
All that being said, for the experiment to actually work you'd need to do the near impossible...
The dropped bullet would have to be in the same horizontal orientation and spinning at the same rate as the shot bullet (150,000ish rpm), so the air resistance (horizontal B.C. so to speak) would be the same. The rifle barrel would have to be perfectly horizontal, so no up/down vector is introduced. I'm still not sure it would work, as there's probably going to be some sort of vertical acceleration in the fired bullet due to aerodynamic lift/drop, if the bullet isn't pointed perfectly straight into the oncoming air.
Too bad MythBusters was cancelled...