Using the Hornady 4DOF calculator to calculate mid-range trajectory for a 215 Berger at 2,800 fps I came up with:
Just under 96 inches or 8 feet. The sine of 1 degree is .017.
.017(sine 1 deg) * 96 (mid-range trajectory) = 1.6 or slightly less than 2 inches.
This is enough to cause a missed X ring at 1,000 yards. I have seen shooters cant left or right to make tiny wind corrections.
Shooting at a pop can size rodent (2.5 wide gopher) at 600:
24 inches (mid-range trajectory @ 600, 75 ELDM @ 3150) * .017 (sine 1 degree) = .4 inches >> no big deal, but then there might be some wind to deal with. Wait for the rodent to lay flat & shoot at the upwind end. 5-degree cant would be almost one gopher width at 600.
Some guys on this forum shoot golf balls at 1,000 and they would be real deadly on gophers @ 600.
1 (sine 90 deg, rifle resting on left side, bolt up) * 96 (mid-range trajectory) = 96 inches, 8 feet, elevation now windage.
.707 (sine 45 deg) * 96 (mid-range trajectory) = 68 inches, 5.7 feet, rifle cant half way between 90 and 0 deg.
.5 (sine 30 deg) * 96 (mid-range trajectory) = 48 inches, 4 feet, rifle cant 30 degrees
Berger data with same .308 215 gr. @ 2800 is real close. This assumes a 1,000 yard zero as sights would be adjusted to hit at this range. Mid-range trajectory about 93 inches.