SD is the weight in relation to its diameter. Given a caliber, the diameter doesn't change, so....whether you want to say the length gives it weight or the weight gives it length, I don't see being a point worth arguing about. Semantics. However, as we can come to understand, it will come out to the higher SD and usually a higher BC. Again it's not just weight. The disconnect seems to be the weight vs weight proportional to the diameter, so again, weight to diameter is length when talking about bullets. "My method" is not my method...it's just is what it is. The original conversation wasnt to you, it was to grease who was out there making up facts and formulas, and specifically said "the heavier the bullet, the higher the BC is" and "SD is not apart of BC." Both of which are false as you can note in my previous post.
Do you know how to calculate the BC though?
The formula you say you know... is wrong, it's not SD over form factor....I litterally took a picture of Bryan litz's book and linked to Berger website with the formula. All you needed to do is copy and paste it if you wanted to just argue and you didn't even get that right. I don't know how else to spoon feed it.
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Dude, I've been playing nice. If you want to be an arrogant *** it would be better if you know what the hell you're talking about.
1) you said "It's just misleading to say mass or weight is a huge contributing factor to BC when its SD=Mass/cross section area."
It's not cross section area (that would be pi xdiaxdia/4) It is the square of the diameter that is used in calculating the SD. (That's in your Berger link)
2): you said "the w/7000 can be rewritten in more school like form of pi x radius^2."
wrong. The w/7000 is converting grains to lbs
3: From your Berger link (did you even read it?) "In words, the Ballistic Coefficient of a bullet is it's sectional density divided by its form factor."
Do you know how to calculate the BC?
Anytime you want to apologize Will be fine.
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