Steve Douglass
Well-Known Member
Macv,
The reason the distance has changed is due to the reduction in the size of the target i.e. 72" to 36", the reticle view i.e. Mils
will go from 2.5 to 1.25. So basically the calculation will be as follows:
Size of Target: 36"
Mils: 1.25
So it's 36"(27.78)/1.25= 800.06 or if you're using my method your 36" target is 100% of the allocated 36" standard. 100%(1000)=1000/ 1.25= 800
Note: The 36" is merely a reference or standard and not actually to be used in the final equation.
The math has to stay consistant. If you feel that no target will ever get larger than 36" then this would work fine. A Prarie Dog @ 12" is 34% of 36", a Deer @ 24" is 67% of 36", and the human torso is approx. 100% of 36". You would then multiply the percentages by 1000 and divide by the mils. Does that help?
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Experience the best, Judge the rest!!
[ 09-15-2004: Message edited by: PracTac ]
The reason the distance has changed is due to the reduction in the size of the target i.e. 72" to 36", the reticle view i.e. Mils
will go from 2.5 to 1.25. So basically the calculation will be as follows:
Size of Target: 36"
Mils: 1.25
So it's 36"(27.78)/1.25= 800.06 or if you're using my method your 36" target is 100% of the allocated 36" standard. 100%(1000)=1000/ 1.25= 800
Note: The 36" is merely a reference or standard and not actually to be used in the final equation.
The math has to stay consistant. If you feel that no target will ever get larger than 36" then this would work fine. A Prarie Dog @ 12" is 34% of 36", a Deer @ 24" is 67% of 36", and the human torso is approx. 100% of 36". You would then multiply the percentages by 1000 and divide by the mils. Does that help?
-----------------------------------------
Experience the best, Judge the rest!!
[ 09-15-2004: Message edited by: PracTac ]