Gravity effects on bullets

[orkan]

Get beyond earth's gravity pull and things become weightless.

They don't become mass-less, however. We simply stop having a convenient way tie their mass to something relative that is widely understood easily by people. lol

If a 50lb object going 100mph hit you in space, you'd feel its "weight."



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[Barbourcreek]

They don't become mass-less, however. We simply stop having a convenient way tie their mass to something relative that is widely understood easily by people. lol

If a 50lb object going 100mph hit you in space, you'd feel its "weight."



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Of course, it's meant in relation to the solver use not actual weight changing .

 

[orkan]

Of course, it's meant in relation to the solver use not actual weight changing .

Yup I understand... I maybe was being a bit pedantic.



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[del2les]

F = G * m1 * m2 / d^2
g = G * m earth / (d earth)^2
W = m * g[/center]

Since the gravitational constant (g) depends on the square of the distance from the center of the earth, we would expect that the weight of an object would decrease with altitude. Let's do a test problem to see how much the weight changes. If an airplane is flying at 35,000 feet (about 7 miles) the distance to the center of the earth is about 4,007 miles. We can calculate the change in the gravitational constant as the square of (4000/4007) which equals .9965. If the airplane weighs 10,000 pounds on the surface of the earth, it weighs 9,965 pounds at 35,000 feet; it has lost 35 pounds, a very small amount compared to 10,000 pounds.

 

[Rok1167]

isaac newton was awesome

f=ma
IYKYK

 

[akmtnhnt]

F = G * m1 * m2 / d^2
g = G * m earth / (d earth)^2
W = m * g[/center]

Since the gravitational constant (g) depends on the square of the distance from the center of the earth, we would expect that the weight of an object would decrease with altitude. Let's do a test problem to see how much the weight changes. If an airplane is flying at 35,000 feet (about 7 miles) the distance to the center of the earth is about 4,007 miles. We can calculate the change in the gravitational constant as the square of (4000/4007) which equals .9965. If the airplane weighs 10,000 pounds on the surface of the earth, it weighs 9,965 pounds at 35,000 feet; it has lost 35 pounds, a very small amount compared to 10,000 pounds.

And a 150gr bullet now weighs..... 149.868gr. At 35k feet. Irrelevant to ballistics even on the top of Everest.

 

[Barbourcreek]

I get the math. It all makes since
But it was just a thought since I have never seen it covered before in shooting.