Doc,
I am trying to understand how to calculate the Eotvos (aka vertical coriolis) on my bullet and I am having a very hard time getting this particular formula to make sense.
For the equasion:
F = 1 - ((2 * Ω *MV/g)*Cos(latitude)*Sin(Azimuth))/g)cos(Lat)*sin(Az)
Could you perhaps provide an example with numbers so that I could plug and chug to see what I am going wrong?
My latitude is 42.185710*N
For argument sake let's say my azimuth us 75*NE from due North
Let's say my muzzle Velocity is 2900fps
F = 1 - ((2 * 0.0000729*2900/32.2)*Cos(42.185710)*Sin(75))
F= 1-((0.42282/32.2)*(0.7409721054)*(0.9659258263)
F= 1-((0.0131310559)*(0.7409721054)*(0.9659258263))
F = 1 - 0.0093982131
F=0.9906017869
1) is this correct?
2) is there any other math applied to this correction value before it is dialed into the scope?
3) Does MV = muzzle Velocity or is M = Mass and V= Velocity as it would be written in physics?
4) What are the specific units of measure for the velocity variable? or for mass*Velocity?
5) (BIG Question) How exactly does one determine vertical coriolis at 1000m, versus 1500m, versus at 2000m?
This equasion does not seem to include any mathematical descriptors for variation at different ranges.
And this is where I am lost.
Every time I try to apply this formula I seem to get 0.999 something for every number I plug in.
It's driving me to madness......
Please help! I would be very grateful if you can point me in the right direction.
My email is
[email protected]
Many thanks
