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Hunting
Long Range Hunting & Shooting
Is a scope level needed?
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<blockquote data-quote="Michael Eichele" data-source="post: 1014691" data-attributes="member: 1007"><p>I'm finding it hard to believe that this thread has generated so many pages and how much 'resistance' there is to using a level.</p><p></p><p>Here is a fact:</p><p></p><p>A simple formula for how much horizontal deviation you will see:</p><p></p><p>Sine of the degree of cant * drop at desired range from boreline. Drop from boreline is NOT corrected for your zero.</p><p></p><p>Based on 0' elevation, 29.92 in. Hg. 78% humidity, 3000'sec MV, BC of .5, scope height of 2". An example would be a drop of 328" at 1000 yards (corrected for a 300 yard zero is 257").</p><p></p><p>The sine of 6 degrees is .10453</p><p></p><p>Take .10453 * 328" and you have 34.28". This is how much horizontal displacement you will have at 1000 yards with a 6 degree cant.</p><p></p><p>Vertical deviation is:</p><p></p><p>(1- cosine of cant degrees) * drop at desired range from boreline. </p><p></p><p>(1-cosine 6) = .00548</p><p></p><p>.00548 * 328 = 1.8" impact low at 1000 yards.</p><p></p><p>I said a simple formula because the reality is its a bit more complicated but this is a VERY very close approximation.</p><p></p><p>Use a level, don't use a level. The choice is yours. I know I don't want to miss by nearly 3 feet at the buck of a lifetime so you will always find a level on my rifles.</p><p></p><p>M</p></blockquote><p></p>
[QUOTE="Michael Eichele, post: 1014691, member: 1007"] I'm finding it hard to believe that this thread has generated so many pages and how much 'resistance' there is to using a level. Here is a fact: A simple formula for how much horizontal deviation you will see: Sine of the degree of cant * drop at desired range from boreline. Drop from boreline is NOT corrected for your zero. Based on 0' elevation, 29.92 in. Hg. 78% humidity, 3000'sec MV, BC of .5, scope height of 2". An example would be a drop of 328" at 1000 yards (corrected for a 300 yard zero is 257"). The sine of 6 degrees is .10453 Take .10453 * 328" and you have 34.28". This is how much horizontal displacement you will have at 1000 yards with a 6 degree cant. Vertical deviation is: (1- cosine of cant degrees) * drop at desired range from boreline. (1-cosine 6) = .00548 .00548 * 328 = 1.8" impact low at 1000 yards. I said a simple formula because the reality is its a bit more complicated but this is a VERY very close approximation. Use a level, don't use a level. The choice is yours. I know I don't want to miss by nearly 3 feet at the buck of a lifetime so you will always find a level on my rifles. M [/QUOTE]
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Is a scope level needed?
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