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Extreme Long Range Hunting & Shooting (ELR)
How High do bullets go in their flight trajectory
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<blockquote data-quote="rammac" data-source="post: 1824541" data-attributes="member: 27761"><p>To answer your question directly; the way the military used to teach this solution to their artillery crews was to use a simple formula:</p><p></p><p>4(t squared) sorry, I can't do exponents so I had to write t squared the way I did</p><p></p><p>t= the time of flight for total range</p><p></p><p></p><p></p><p>So all you need to do is square the time of flight (to the range you are interested in) and multiply by 4 and you will get the height in yards. Multiply the answer by 3 and you will get the height in feet.</p><p></p><p>So lets say you shoot a .308 caliber, 168gr bullet at 1000 yards.</p><p></p><p>The time of flight for 1000 yards (from my ballistic software's trajectory chart) is approx. 1.6452 seconds</p><p></p><p>(1.6452 x 1.6452 ) x 12 = 32.5 feet</p><p></p><p>So the highest that the bullet will be, relative to the muzzle is, approximately 32.5 feet higher. If you are standing then you add the distance between the muzzle and the ground.</p><p></p><p>There is an error in this estimate due to rounding and precision but it's close enough to estimate wind conditions.</p><p></p><p>(Sorry, I had to correct my math but these are the correct formula and solutions)</p></blockquote><p></p>
[QUOTE="rammac, post: 1824541, member: 27761"] To answer your question directly; the way the military used to teach this solution to their artillery crews was to use a simple formula: 4(t squared) sorry, I can't do exponents so I had to write t squared the way I did t= the time of flight for total range So all you need to do is square the time of flight (to the range you are interested in) and multiply by 4 and you will get the height in yards. Multiply the answer by 3 and you will get the height in feet. So lets say you shoot a .308 caliber, 168gr bullet at 1000 yards. The time of flight for 1000 yards (from my ballistic software's trajectory chart) is approx. 1.6452 seconds (1.6452 x 1.6452 ) x 12 = 32.5 feet So the highest that the bullet will be, relative to the muzzle is, approximately 32.5 feet higher. If you are standing then you add the distance between the muzzle and the ground. There is an error in this estimate due to rounding and precision but it's close enough to estimate wind conditions. (Sorry, I had to correct my math but these are the correct formula and solutions) [/QUOTE]
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How High do bullets go in their flight trajectory
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