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Rifles, Reloading, Optics, Equipment
Gunsmithing
Lug setback? What am I missing?
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<blockquote data-quote="cohunt" data-source="post: 1820419" data-attributes="member: 94491"><p>see the calcs--- lets take a set pressure to simplify--62,000 psi chamber pressure--- that same pressure is exerted on a .470 bolt face vs a .585 bolt face --- same pressure exerted over a larger area equals more force, dont care how big the lugs are if they are equal in both guns the lugs in the larger bolt face will see higher forces</p><p></p><p>think of it this way--- 62000 psi is pounds per square inch so the amount of force is dependent upon the area it exerts the force over-- a .470" bolt face is .1735 square inches -- a .585 bolt face is .2712 square inches, soooo at 62000 pounds per square inch you would take 62000 x .1735 = 10757 pounds of force for the .470" bolt face---BUT 62000x .2712 would be 16814 pounds of force for the larger .585" bolt face---make sense now?</p></blockquote><p></p>
[QUOTE="cohunt, post: 1820419, member: 94491"] see the calcs--- lets take a set pressure to simplify--62,000 psi chamber pressure--- that same pressure is exerted on a .470 bolt face vs a .585 bolt face --- same pressure exerted over a larger area equals more force, dont care how big the lugs are if they are equal in both guns the lugs in the larger bolt face will see higher forces think of it this way--- 62000 psi is pounds per square inch so the amount of force is dependent upon the area it exerts the force over-- a .470" bolt face is .1735 square inches -- a .585 bolt face is .2712 square inches, soooo at 62000 pounds per square inch you would take 62000 x .1735 = 10757 pounds of force for the .470" bolt face---BUT 62000x .2712 would be 16814 pounds of force for the larger .585" bolt face---make sense now? [/QUOTE]
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Lug setback? What am I missing?
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